В продолжение темы - я ни разу не химик но это вы и так уже поняли)
Вот что пишут наши братья забугорные. Может кто-то на пальцах объяснит?
This depends a bit from the alkalinity. Alkalinity and pH together tell how many bicarbonate (HCO3-) and carbonate (CO3--) ions are in the water. When adding hydroxide (OH-) following reaction takes place:
HCO3- + OH- --> CO3-- + H2O
If your alkalinity is high the pH-shift will be smaller than if the alkalinity is low because the proportion of bicarbonate and carbonate ions shifts less when larger numbers of both are present.
At 7 dKH alkalinity you have ca. 2.5 mval/l total alkalinity (TA) of which at pH 8 are 89.8 % HCO3- and 6.7 % CO3--.
2.5 * 89.8 % = 2.245 mval/l HCO3-; 2.5 * 6.7 % = 0,1675 mval/l CO3--; together sums up to 2.4125 or 96.5 % of TA bicarbonate-carbonate-alkalinity
1 l of saturated calcium hydroxide (74.1 g/mol) solution is 1.7 g/l Ca(OH)2 or 22.9 mmol/l or twice as many mval/l, 45.9 mval/l.
If you add 1 l of this solution to 100 l of saltwater at 7° dKH and pH 8 you will shift the proportions by 45.9 mval/l : 100 = 0.459 mval/l. This will result in:
2.245 mval/l - 0.459 mval/l HCO3- = 1.786 mval/l HCO3- and 0.1675 mval/l + 0.459 mval/l CO3-- = 0.6265 mval/l CO3--
of 2.4125 bicarbonate-carbonate-alkalinity. The bicarbonate-carbonate alkalinity has not altered but their relative proportions and the contribution to total alkalinity has change significantly.
Of 2.5 mval/l total alkalinity now 1.786 mval/l or 71.44 % are HCO3- and 0.6265 mval/l or 25.06 % are CO3--;
Still 96.5 % of total alkalinity are bicarbonate-carbonate-alkalinity, but it has shifted from 89.8 % HCO3- + 6.7 % CO3-- to 71.44 % HCO3- + 25.06 % CO3--
Unfortunately my calculatory skills end here and I have no table how this translates to pH.
Now you can do the same calculation with any other alkalinity. 1 dKH = 0.3566 mval/l alkalinity.